Math, asked by lohithpadmanabhuni, 4 months ago

8.
2.
The equation of the circle with radius 3
and centre as the point of intersection
of the lines 2x+3y = 5, 2x - y =l is
1) x² + y2 = 9
2) x² + y2 - 2x - 2y - 7 = 0
3).x + y2 - 2x - 2y +7=0
4)x2+ y2 +9=0

Answers

Answered by Omkarborde100
2

Answer:

Answer: x² + y² -2x -2y - 7 = 0. Step-by-step explanation: the point of intersection of the lines 2x+3y=5,2x-y=1. y = 1 , x = 1 ...

14 votes

Answer:x² + y² -2x -2y - 7 = 0Step-by-step explanation:the point of intersection of the lines 2x+3y=5,2x-y=1y = 1 , x = 1 centre = ( 1, 1 ) The equation

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