8.23: The minimum energy required to overcome
the attractive forces between an electron and
the surface of Ag metal is 5.52 x 10-19 J. What
will be the maximum kinetic energy of
electron ejected out from Ag which is being
exposed to UV-light of 2 = 360 Aº ?
Answers
Answer:
for better understanding.
Sample testcasesJumping
numbers but 796 and 89098 are notin sorted
Sample testcasesJumping
numbers but 796 and 89098line of the input containssorted order. Jump to
example for better understanding.
Sample testcasesJumping
numbers but 796 and 89098 are notin sorted
WLAN
The first line of the input containssorted order. Jump to
example for better understanding.
Sample testcasesJumping
numbers but 796 and 89098 are notin sorted
Sample testcasesJumpingattractive forces between an electron and
the surface of Ag metal is 5.52 x 10-19 J. What
will be the maximum kinetic energy of
electron ejected out from Ag which is being
exposed to UV-light of 2 = 360 Aº ?
numbers but 796 and 89098
Answer:
K.E = hc/lamda -work function
given : work function=5.52 ×10^-19
K.E = [(6.626×10^-34 ×3×10^8) /360 10^-10]-5.52×10^-19
= 49.68 × 10^-19
K.E= 49.68 ×10^-19