+ ? (8)+ (27) = ? 7. ( +(/3 ? (a) 4 (b) 5 (c) 6
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Answer:
27(x+y)3+8(2x−y)3
Above terms can be written as,
33(x+y)3+23(2x−y)3
(3(x+y))3+(2(x−y))3
We know that,a3+b3=(a+b)(a2−ab+b2)
Where,a=3(x+y),b=2(x−y)
=[3(x+y)+2(2x−y)][(3(x+y))3−(3(x+y)×2(2x−y))+(2(2x−y))2]
=[3x+3y+4x−2y][9(x+y)2−6(x+y)(2x−y)+4(2x−y)2]
=(7x−y)[9(x2+y2+2xy)−6(2x2−xy+2xy−y2)+4(4x2+
27(x+y)3+8(2x−y)3
Above terms can be written as,
33(x+y)3+23(2x−y)3
(3(x+y))3+(2(x−y))3
We know that,a3+b3=(a+b)(a2−ab+b2)
Where,a=3(x+y),b=2(x−y)
=[3(x+y)+2(2x−y)][(3(x+y))3−(3(x+y)×2(2x−y))+(2(2x−y))2]
=[3x+3y+4x−2y][9(x+y)2−6(x+y)(2x−y)+4(2x−y)2]
=(7x−y)[9(x2+y2+2xy)−6(2x2−xy+2xy−y2)+4(4x2+
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Answered by
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Answer:
7 ? (8)+ (27) = ? 7. ( +(/3 ? (a) 4 (b) 5 (c) 6
=7
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