Math, asked by chandralekha24, 11 months ago

8/27 a ^7 b^2 +4/9a^5b^2 plz answer my question please sir​

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Answered by welcome101
1

Answer:

 \frac{8}{27} a {}^{7} b {}^{2}  +  \frac{4}{9} a {}^{5} b {}^{2}  \\  ( \frac{2}{3} ) {}^{3} a {}^{7} b {}^{2}  +  (\frac{2}{3} ) {}^{2} a {}^{5} b {}^{2}  \\ ( \frac{2}{3} ) {}^{2} a {}^{5} b {}^{2}  \times ( \frac{2}{3} a {}^{2}  + 1) \\  \\ this \: is \: your \: answer


chandralekha24: but I should get the answer 4/9a^5b^2(2/3a^2+1
chandralekha24: kk
chandralekha24: it's correct
welcome101: see there I wrote (2/3)^2 = (4/9) rest of thing are same it's value/answer is same. there is no any difference.
welcome101: ok, did u get it
chandralekha24: kk
chandralekha24: it's correct
welcome101: ok,
chandralekha24: OK thanks
welcome101: welcome
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