Math, asked by krishnaagrawal7150, 1 year ago

[8/27]^x-1= [9/4]^2x+1 find the value of x

Answers

Answered by littyissacpe8b60
12

  2³ˣ⁺²    =  3⁴ˣ⁺²  

  3³ˣ⁺²         2⁴ˣ⁺²


(2³ˣ ⁺²) (2⁴ˣ⁺²)  = ( 3⁴ˣ⁺² ) (3³ˣ⁺²)


2⁷ˣ⁺⁴  = 3⁷ˣ⁺⁴

(2/3)⁷ˣ⁺⁴

7x + 4 = 0

7x = ⁻4

x = ⁻4/7


Anonymous: Wth!! Wrong solution
Answered by emily1532
1

Answer:

x=1/7

Step-by-step explanation:

(8/27)^x-1=(9/4)^2x+1

as we know 8=2³,27=3³,9=3² and 4=2²

substituting the squares and cubes,

we get,

(2/3)^3x-3 = (3/2)^4x+2

-> as we know a^x=1/a^-x

we shift RHS upside-down so,

we get,

RHS=(2/3)^-4x-2

since both the bases of LHS and RHS are equal,

3x-3= -4x-2

the final answer will be x=1/7

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