Question

8/27x^3-1/8y^3 Please factorise

Answer 1

Given: The term 8/27x^3 - 1/8y^3

To find: Factorise the given term.

Solution:

• Now we have given the term 8/27x^3-1/8y^3

• We can rewrite it as:

               8/27x^3-1/8y^3 = (2x/3)^3 - (y/2)^3

• Now we know the formula:

               (a^3 - b^3) = (a - b)(a^2 + ab + b^2)

• So applying this for given term, we get:

               (2x/3)^3 - (y/2)^3 = (2x/3 - y/2) x ((2x/3)^2 + (2x/3)(y/2) + (y/2)^2)

                                            = (2x/3 - y/2) x (4x^2/9 + xy/3 + y^2/4)

Answer:

             So after factoring, it comes out to be

             (2x/3 - y/2) x (4x^2/9 + xy/3 + y^2/4)

Answer 2

Answer:

(2x/3 - y/2) x (4x^2/9 + xy/3 + y^2/4)

Step-by-step explanation:

yep here ya go