Question

8.2L of an ideal gas weighs 9.0 g at 300 K and 1 atm pressure. The molecular mass of gas is
(A) 9
(B) 27
(C) 54
(D) 81​

Answer 1

Answer:

8.2L of an ideal gas weighs 9.0 g at 300 K and 1 atm pressure. The molecular mass of gas is

(A) 9

(B) 27 ✔✔

(C) 54

(D) 81

Answer 2

Answer:Answer:B. 27

Explanation:

Explanation:using the formula pv =nrt

Where p is the pressure

V is the volume

R is a constant equal to 0.0821

T is the temperature in k

N is the number of moles

Application

To get ur number of mole make n the subject of d formula

The equation become pv/rt=n

1*8.2/0.0821*300=n

n=0.3329

Since number of mole =mass/molecular weight

Therefore mass/number of moles=molecular weight

9/0.3329=27

Therefore answer=27