Question

8. ਬਿੰਦੂਆਂ (-3, 10) ਅਤੇ (6, 8) ਨੂੰ ਮਿਲਾਉਣ ਵਾਲੇ ਰੇਖਾਖੰਡ ਨੂੰ
ਬਿੰਦੂ (1,6) ਕਿਸ ਅਨੁਪਾਤ ਵਿੱਚ ਵੰਡਦਾ ਹੈ ?
Find the ratio in which the line segment joining the points
( 3, 10) and (6, 8) is divided by (-1, 6).​

Answer 1

Answer:

the section formula, if a point (x,y) divides the line joining the points

(x 1 ,y 1) and (x 2 ,y 2 ) in the ratio m:n, then (x,y)=( m+n mx 2+nx 1 , m+n my 2 +ny 1)

Let the ratio be k:1

Substituting (x 1,y 1 )=(−3,10) and (x 2 ,y y )=(6,−8) in the section

formula, we get ( k+1 k(6)+1(−3) , k+1

k(−8)+1(10)

)=(−1,6)

( k+1

6k−3

,

k+1

−8k+10

)=(−1,6)

Comparing the x - coordinate,

k+1

6k−3

=−1

=>6k−3=−k−1

7k=2

k=

7

2

Hence, the ratio is 2:7