Question

8^3 ÷ 16^2 * 32 = 2^x-4 ÷ 4^2
options
A 12
B 18
C 10
D 14 ​

Answer 1

Answer:

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Answer 2

$8 {}^{3} \div {16}^{2} \times 32 = 2 {}^{x } - 4 \div 4 {}^{2}$

$(512 \div 256) \times 32 = 2 {x}^{2} - (4 \div 16)$

$2 \times 32 = 2 {}^{x} - 4$

$64 = - 2x$

$64 ÷ 2 = x$

$32$