Question

-8 ÷ -3/16
evaluate the above equation

Answer 1

Answer: ∫ log (x + 1) - log x dx/x (x + 1) = -1/2(log (x + 1))2 - 1/2 (log x)2 - log (x + 1) log x + C

Here is a detailed explanation.

Explanation:

Let log (x+1) - log x = t.

On differentiating the above equation with respect to 'x', we get

1/(x+1) - 1/x = dt/dx

d/dx log x = 1/x

On solving this we'll get,

-1/x (x+1) = dt/dx

dx = -x (x+1)dt

Answer 2

Answer:

Answer is in the attachment

Step-by-step explanation:

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