[(– 8) × (– 3)] × (– 4) is not equal to
(a) (– 8) × [(– 3) × (– 4)] (b) [(– 8) × (– 4)] × (– 3)
(c) [(– 3) × (– 8)] × (– 4) (d) (– 8) × (– 3) – (– 8) × (– 4)
Solution:
(d) (– 8) × (– 3) – (– 8) × (– 4)
[(– 8) × (– 3)] × (– 4)
= (– 8) × [(– 3) × (– 4)]
= [(– 8) × (– 4)] × (– 3)
= [(– 3) × (– 8)] × (– 4
But, [(– 8) × (– 3)] × (– 4) ≠ [(– 8) × (– 3)] × (– 4)
Answers
Answered by
9
Answer:
hope this will help to u ....
Attachments:
Similar questions