Math, asked by avijitp392, 2 months ago

8(3+se)+8(3-sr)/(3-sr) (3-sr)=6​

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Answered by aymankskhan
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Answer:

Step-by-step explanation: herefore, the distances vary significantly from 287–290 pm for d(Gd 3+ –Se 2 −) to 310–319 pm plus 340 pm for d(Sr 2+ –Se 2−), see Table 5. The highest degree of differentiation among the high-charged cations is reached in SrCuLuSe 3 with the smallest M 3+ cation (closed-shell 4f 14 Lu 3+; r i = 86 pm, CN = 6 ). Although the coordination number of Lu 3+ remains unchanged (CN = 6)

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