Question

8. 3 years ago Juma was 3 times as old as Ali. In 2 years time the sum of their ages will be
62. Determine their present ages. (3mks)

Answer 1

J+2+A+2 = 62

J+A+4 = 62

J+A = 58

J = 58-A

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J-3 = 3(A-3) SUBSTITUTE FOR J

58-A-3 = 3A-9

55-A = 3A-9 Add A and 9 to both sides

64 = 4A

A = 16

Ali is 16 and Juma is:

J = 58-A = 58-16 = 42

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Check: In 2 years:

42+2+16+2 = 62

44+18 = 62 Correct