Question

8(3a_2b) ^2_10(3a_2b)​

Answer 1

Let y=8(3a−2b) 2−10(3a−2b)

taking (3a−2b) common we get

y=(3a−2b)[8(3a−2b)−10]

y=(3a−2b)[24a−16b−10]

on solving we get

y=72a 2−48ab−30a−48ab+32b 2+20b

y=72a 2+32b 2 −96ab−30a+20b

y=72a 2−30a+32b 2+20b−96ab.