Question

8(3a-2b)2 -10(3a-2b)

Answer 1

The factorisation of 8$(3a-2b)^2$ - 10(3a - 2b) = 2(3a - 2b)(12a - 8b - 5)

Step-by-step explanation:

We have,

8$(3a-2b)^2$ - 10(3a - 2b)

To find, the factorisation of 8$(3a-2b)^2$ - 10(3a - 2b) = ?

∴ 8$(3a-2b)^2$ - 10(3a - 2b)

= (2 × 4) $(3a-2b)^2$ - (2 × 5) (3a - 2b)

Taking 2(3a - 2b) as common, we get

= 2(3a - 2b)[4(3a - 2b) - 5]

= 2(3a - 2b)(12a - 8b - 5)

∴ The factorisation of 8$(3a-2b)^2$ - 10(3a - 2b) = 2(3a - 2b)(12a - 8b - 5)

Answer 2

solution:-

=> 8(3a-2b)² - 10(3a - 2b)

= 8 [(3a)²-2(3a×2b)+(2b)²] -10(3a-2b)

= 8 [9a² - 12ab + 4b² ] - 10(3a - 2b)

= 72a² - 96ab + 32b² - 30a + 20 b

= ½[36 a² - 48ab + 16 b² - 15a + 10b]

i hope it helps you.