Math, asked by lordanmol1309, 1 day ago

8(3x - 2y)^2 - 6x +4y -1

Answers

Answered by sivasankaranshiyam20
0

Answer:

=(6x-4y-1)(12x-8y+1)

8(3x-2y)^2-6x+4y-1

=8(3x-2y)^2-2(3x-2y)-1

let 3x-2y=a

=8a^2-2a-1

= -4a(2a-1)+1(2a-1)

=(2a-1) (4a+1)

putting the value of a,

[2(3x-2y)-1] [4(3x-2y)+1]

=(6x-4y-1) (12x-8y+1)

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