8(3x-5)-7(2x-8)=36 solve
Answers
Answer:
How to solve your problem
8
(
3
−
5
)
−
7
(
2
−
8
)
=
3
6
8(3x-5)-7(2x-8)=36
8(3x−5)−7(2x−8)=36
Solve
1
Distribute
8
(
3
−
5
)
−
7
(
2
−
8
)
=
3
6
{\color{#c92786}{8(3x-5)}}-7(2x-8)=36
8(3x−5)−7(2x−8)=36
2
4
−
4
0
−
7
(
2
−
8
)
=
3
6
{\color{#c92786}{24x-40}}-7(2x-8)=36
24x−40−7(2x−8)=36
2
Distribute
2
4
−
4
0
−
7
(
2
−
8
)
=
3
6
24x-40{\color{#c92786}{-7(2x-8)}}=36
24x−40−7(2x−8)=36
2
4
−
4
0
−
1
4
+
5
6
=
3
6
24x-40{\color{#c92786}{-14x+56}}=36
24x−40−14x+56=36
3
Add the numbers
2
4
−
4
0
−
1
4
+
5
6
=
3
6
24x{\color{#c92786}{-40}}-14x+{\color{#c92786}{56}}=36
24x−40−14x+56=36
2
4
+
1
6
−
1
4
=
3
6
24x+{\color{#c92786}{16}}-14x=36
24x+16−14x=36
4
Combine like terms
2
4
+
1
6
−
1
4
=
3
6
{\color{#c92786}{24x}}+16{\color{#c92786}{-14x}}=36
24x+16−14x=36
1
0
+
1
6
=
3
6
{\color{#c92786}{10x}}+16=36
10x+16=36
5
Subtract
1
6
16
16
from both sides of the equation
1
0
+
1
6
=
3
6
10x+16=36
10x+16=36
1
0
+
1
6
−
1
6
=
3
6
−
1
6
10x+16{\color{#c92786}{-16}}=36{\color{#c92786}{-16}}
10x+16−16=36−16
6
Simplify
Subtract the numbers
Subtract the numbers
1
0
=
2
0
10x=20
10x=20
7
Divide both sides of the equation by the same term
1
0
=
2
0
10x=20
10x=20
1
0
1
0
=
2
0
1
0
\frac{10x}{{\color{#c92786}{10}}}=\frac{20}{{\color{#c92786}{10}}}
1010x=1020
8
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
2
Answer:
24x-40-14x+54=36
24x-14x-40+54=36
10x+14=36
10x=36-14
10x=22
x=22/10
or x=2.2