{8,−4,2,−1,...} find the sum of the first 6 terms
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Answer:
a=8
d=-12
n=6
S6=?
Step-by-step explanation:
Sn=n/2(2a+(n-1)d)
S6=6/2(2(8)+(6-1)-12)
S6=3(16+(5)-12)
S6=3(16-60)
S6=3(-44)
S6=-132
consider positive number as 132
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