-. 8.4 g sodium bicarbonate (NaHCO3) was added in 6 g
acetic acid (CH2COOH). CO, escapes out and mass of
sodium acetate and water formed was found to be 10
g. Calculate the mass of CO2 escaped.in this question answer will come 4.4g
Answers
Answered by
0
Explanation:
The mass of residue, is CH
3
COONa solution, should be 24g of CH
3
COONa solution.
In this reaction, sodium bicarbonate reacts with acetic acid to produce sodium acetate, carbon dioxide and water
NaHCO
3
+CH
3
COOH⟶CH
3
COONa+CO
2
+H
2
O
According to law of conversation of masses,
total masses of reactants = total masses of products
reactants are 8.4g NaHCO
3
and 20g CH
3
COOH.
total mass of reactants is =28.4g
mass of residue = (28.4g reactants mass) − (4.4g CO
2
)
= 24.0g residue (sodium acetate solution)
mass of residue is thus 24 grams.
Answered by
1
Answer:
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Explanation:
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