Question

-8/44 + -9/33 = ??

answer this pls ​

Answer 1

Answer:

$\frac{-8}{44} + (\frac{-9}{33} )=\frac{-5}{11}$

Step-by-step explanation:

First, make the fraction as like fractions

$-\frac{8}{44} =-\frac{8 \div 4}{44 \div 4} = -\frac{2}{11} \\-\frac{9}{33} =-\frac{9 \div 3}{33 \div 3} = -\frac{3}{11}$

Now add given fraction

$\frac{-8}{44} + (\frac{-9}{33} )=\frac{-2}{11} + (\frac{-3}{11} )\\=\frac{-2}{11} - \frac{ 3}{11} \\=\frac{-2-3}{11} \\=\frac{-5}{11}$

Answer 2

Answer:

Hence, $-\frac{8}{44} + (-\frac{9}{33})=-\frac{5}{11}$

Step-by-step explanation:

In context to question asked,

We have to determine the value when -8/44 + -9/33  are solved.

As we know that,

When negative sign (-) is multiplied to positive (+) sign then the result will be negative sign.

So, we can rewrite the above expression as,

$-\frac{8}{44} + (-\frac{9}{33})\\=>-\frac{8}{44} -\frac{9}{33}$

As here the numerator and denominator of both the fraction can be simplified by dividing by 4 (in case of first fraction) and by 3 (in case of second fraction)

Thus we will get,

$=>-\frac{2}{11} -\frac{3}{11}\\=>\frac{-2-3}{11}\\=>-\frac{5}{11}$