8-4a-2a³+a⁴ solve this
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8−4a−2a
3
+a
4
By taking 4 as common in the first two terms and a
3
as common in the second two term
8−4a−2a
3
+a
4
=4(2−a)−a
3
(2−a)
So we get,
8−4a−2a
3
+a
4
=(2−a)(4−a
3
)
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