Question

8 – 4l – 4m – 2lm – 4n + 2ln + 2mn – lmn

l is not 1, its an alphabet L
Please factorise it

Answer 1

Answer:

8 – 4l – 4m – 2lm – 4n + 2ln + 2mn – lmn. 1. See answer. Add answer+5 pts. Log in to add comment. rahulkandhasami0 is ...

Answer 2

The factors are $(2-m)(2-n)(2-l)$

Step-by-step explanation:

Given: The algebraic expression $8-4l-4m-2lm-4n+2ln+2mn-lmn$

To find: The factors of the given expression

Solution:

• Taking common terms outside and making groups, we get

$4( 2-l) - 2m(2-l) -2n(2-l) +mn(2-l)$

• It can be seen that the terms in the bracket are the same, so we can simplify the above expression as

$[4-2m-2n+mn](2-l)$

• Again taking common terms

$[2(2-m) - n(2-m)](2-l)$

$(2-m)(2-n)(2-l)$

Hence, the factors of the given algebraic expression are (2-m)(2-n)(2-l)