Question

8.5.3 EQUATION FOR POSITION-VELOCITY
RELATION
From the velocity-time graph shown in
8.8. the distances travelled by the object
time t moving under uniform acceleration
is ren by the area enclosed within the
perium OABC under the graph. That is
area of the trapezium OABC​

Answer 1

Answer:

Here is your answer dear which may help you:-

Explanation:

Therefore,

s = Area of trapezium OABC

=(OA + BC) × OC / 2

Now, substituting OA = u , BC = v and OC = t, we get:

s = ( u+v ) t / 2 (Eq. 8.1)

From the velocity-time relation (Eq.8.6) we get,

t = ( v - u ) / a

Using Eqs. (8.11) and (8.12) we have,

s = (v+u)(v-u) / 2a

OR

2as = (2as=v2−u2).

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