Question

√8 + √50 / √162 - √98
Solve plz

Answer 1

Answer:

=$2 \sqrt{2 } + 5 \sqrt{2} + 9 \sqrt{2} - 7 \sqrt{2} \\ =9 \sqrt{2}$=√81

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Answer 2

ANSWER:

To Solve:

• (√8 + √50)/(√162 - √98)

Solution:

We need to solve:

$\implies\dfrac{\sqrt8+\sqrt{50}}{\sqrt{162}-\sqrt{98}}$

We will now change the surds, into standard form so that, it is easy to solve.

1. √8

⇒ √8 = √(2×2×2) = 2√2

2. √50

⇒ √50 = √(2×5×5) = 5√2

3. √162

⇒ √162 = √(2×3×3×3×3) = 9√2

4. √98

⇒ √98 = √(2×7×7) = 7√2

So,

$\implies\dfrac{\sqrt8+\sqrt{50}}{\sqrt{162}-\sqrt{98}}$

$\implies\dfrac{2\sqrt2+5\sqrt2}{9\sqrt2-7\sqrt2}$

So,

$\implies\dfrac{7\sqrt2}{2\sqrt2}$

Cancelling, the √2,

$\implies\dfrac{7\sqrt2}{2\sqrt2}$

$\implies\dfrac{7}{2}$

Therefore,

$\implies\bf\dfrac{\sqrt8+\sqrt{50}}{\sqrt{162}-\sqrt{98}}=\dfrac{7}{2}$