8^6
6
÷8^×
×
8 raise to power 6-5=8 powder ×
8= power ×
bases are some
therefore×=1
Answers
Answer:
Exercise 12.1
Question 1:
Evaluate:
(i) 3-2 (ii) (-4)-2 (iii) (1/2)-5
Answer:
(i) 3-2 = 1/32 = 1/9 [a-m = 1/ am]
(ii) (-4)-2 = 1/42 = 1/16 [a-m = 1/ am]
(iii) (1/2)-5 = (2/1)5 = 25 = 32 [a-m = 1/ am]
Question 2:
Simplify and express the result in power notation with positive exponent:
(i) (-4)5 ÷ (-4)8 (ii) (1/23)2 (iii) (-3)4 * (5/3)4 (iv) (3-7 * 3-10) * 35
(v) 2-3 * (-7)3
Answer:
(i) (-4)5 ÷ (-4)8 = (-4)5-8 [am ÷ an = am-n]
= (-4)-3
= 1/(-4)3 [a-m = 1/ am]
= -1/64
(ii) (1/23)2 = 12/(23)2 [(a/b)m = am/bm]
= 1/ 23*2 [(am)n = am*n]
= 1/26
= 1/64
(iii) (-3)4 * (5/3)4 = (-3)4 * (54/34 ) [(a/b)m = am/bm]
= (3)4 * (54/34 ) [(-a)m = am when m is an even number]
= (3)4-4 * 54
= 54
(iv) (3-7 * 3-10) * 35 = 3-7-10+5 [am * an = am+n]
= 3-17+5
= 3-12
= 1/312 [a-m = 1/ am]
(v) 2-3 * (-7)-3 = 1/23 * 1/(-7)-3 [a-m = 1/ am]
= 1/{(-7)3 * 23 }
= 1/(-7 * 2)3 [am * bm = (a * b)m]
= 1/(-14)3
= -1/(14)3 [(-a)m = -am when m is an odd number]
i hope its helpful for you
