Question

8
8)
If sinP=3/5, then find cosP=...​

Answer 1

Answer:

$\frac{ \sqrt{34} }{5}$

Step-by-step explanation:

let.

$\sin(p ) = \frac{3k}{5k}$

then

p = 3K. and h = 5K

$b \: = \: \sqrt{(5k)^{2} + {(3k)^{2} } } \\ = \sqrt{25 {k}^{2} + 9 {k}^{2} } \\ = \sqrt{34 {k}^{2} } \\ = k \sqrt{34}$

$\cos(p) = \: \frac{b}{h} \\ = \frac{k \sqrt{34} }{5k} \\ = \frac{ \sqrt{34} }{5}$

PLZ MARK ME AS THE BRAINLIEST !!!