Question

8,9,10,11&12pleasequestion 8 9 10 11 and 12 please I want it please please please I will follow you

Answer 1

Q8
let the length of leg be 3x&4x
area=1*3x*4x/2
given area=1014cm^2
6xsq=1014.......IN PICTURE

Answer 2

Heya !!!

QUESTION :- Find the length of the height of an equilateral triangle of side 24 cm.

ANSWER :-

Side = 24 cm.

We know that area of equilateral triangle is ..
$a = \frac{ \sqrt{3} }{4} {s}^{2}$
So....
$Area \: = \: \frac{ \sqrt{3} }{4} \times 24 \times 24 \\ = \sqrt{3} \times 6 \times 24 \\ = 1.73 \times 144 \\ = 249.12 \: {cm}^{2}$
As base is 24 cm.

Also, area of triangle is ..
1/2× bh.

Therefore,
Area = 1/2×bh
249.12 = 1/2 × 24 × h
h = 249.12/12
h = 20.76 cm.

Hope it helps