Question

8→9→7→8→6→7→? what is the answer? ​

Answer 1

Answer:

answer is 5 I think so

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Answer 2

Answer:

Solution :

D.r.'s of AB−→− are (4,−8),(6,−2),(−7−0),i.e.,−4,4,−7.

∣∣∣AB−→−∣∣∣=(−4)2+42+(−7)2−−−−−−−−−−−−−−−−−−√=(16+16+49−−−−−−−−−−√=81−−√=9.

∴d.c.'s of AB−→− are −49,49,−79.

D.r.'s of CD−→− are (−9+3),(−2−1),(4−2),i.e.,−6,−3,2.

∣∣∣CD−→−∣∣∣=(−6)2+(−3)2+22−−−−−−−−−−−−−−−−−−√=36+9+4−−−−−−−−−√=49−−√=7.

∴D.c.'s of CD−→− are −67,−37,27.

Let θ be the acute angle between AB−→−andCD−→−. Then.

cosθ=∣∣∣(−49)×(−67)+(49)×(−37)+(−79)×(27)∣∣∣

=∣∣∣2463−1263−1463∣∣∣=∣∣∣−263∣∣∣=263.

∴θ=cos−1(263).

Hence, the required angel between AB −→−andCD −→− is cos_1(263).