Question

8-9 A piece of wire is in the form of rectangle with demensions 24 cm and 20 cm. It is reshaped and bent into the form of a circle Calculate the radius of this circle .
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Answer 1

Answer:

Step-by-step explanation:

perimeter of rectangle = 2(l + b)

= 2(26 + 18)

= 88m

circumference of the circle = 88m

2πr = 88

r = 88 / ( 2 × 3.14 )

= 14.01 m or 14 m

Answer 2

Answer:

14 cm

Step-by-step explanation:

We know that, the perimeter of a rectangle is 2(l+b)

Therefore,

$2(24+20)\\ = 2 * 44\\ = 88$

Now, the same rectangle is reshaped and bent, so perimeter remains the same. Hence perimeter of rectangle = Circumference (perimeter of circle)

Circumference (perimeter of circle) =

$2\pi r = 88\\\pi = 22/7\\\\hence, 2r = 88 / 22/7\\= 2r = 88*7/22\\ 2r = 28\\ r = 28/2\\ = 14$

Hope it helps!

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