Question

8:9. The ratio of their expenses is 9:11. If each
one saves 28,000, find their income.

Answer 1

Step-by-step explanation:

Let their salaries be 9x and 7x.

Let their expenditure be 4y and 3y.

According to the question,

9x−4y=2000 —(1)

7x−3y=2000 —(2)

From (1)

x=

9

2000+4y

—(3)

On putting x in (2), we get

7×

9

(2000+4y)

−3y=2000

9

(14000+28y)

−3y=2000

9

14000+28y−27y

=2000

14000+y=18000

y=4000

Now, put y in (3)

x=

9

2000+4×4000

x=

9

2000+16000

x=

9

18000

=2000

So,

Salary of first person =9×2000=Rs. 18000

Salary of second person =7×2000=Rs. 14000

Answer 2

Step-by-step explanation:

given 8:9

and expenditure is 9:11

let it be

8x-28,000 / 9x - 28,000 = 9/11

11 [8x-28,000] = 9 [ 9x-28,000]

88× - 308000 = 81x - 252000

get x terms one side

88x - 81x = 308000 - 252000

7X = 56000

x = 8000

hence 1st person is 8x = 8 x 8000

2 nd person is 9x = 9 x 8000

1 st person = 64,000

2nd personn is 72,000