Question

8- A 20 Ω resistor is placed across potential difference of 0.22kV. Find the current drop across that resistor. If the voltage now reduced to 0.11kV, what will be the new value of current?

Answer 1

$i 1= \frac{v1}{r} \\ i1 = \frac{220}{20} = 11 \\ i2 = \frac{110}{20} = 5.5 \\ current \: drop = 11 - 5.5 = 5.5$

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