8. A 5 cm tall object is placed perpendicular to the principal axis of a convex lens
of focal length 20 cm. The distance of the object from the lens is 10 cm. Find the
size of the image formed, using the lens formula.
Answers
Answer:
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Explanation:
The size of the image is 10 cm and the image is real and inverted
Given that,
Height of object h = 5 cm
Focal length f = 20 cm
The distance of the object u = -30 cm
Using lens's formula
\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}
f
1
=
v
1
−
u
1
\dfrac{1}{20}=\dfrac{1}{v}-\dfrac{1}{-30}
20
1
=
v
1
−
−30
1
\dfrac{1}{v}=\dfrac{1}{60}
v
1
=
60
1
v = 60v=60
The image is formed at 60 cm on the other side from the lens.
The magnification is
m = \dfrac{v}{u}m=
u
v
m = \dfrac{60}{-30}m=
−30
60
m = -2m=−2
The image is real, inverted .
Size of the image,
m = \dfrac{h'}{h}m=
h
h
′
-2 = \dfrac{h'}{5}−2=
5
h
′
h' = -10 cmh
′
=−10cm
Hence, The size of the image is 10 cm and the image is real and inverted.
Question:
- A 5 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is 10 cm. Find thesize of the image formed, using the lens formula.
☞Solution:
➝Let us assume something:
- Object distance→ u
- Image distance→ v
- Focal length→ f
- Size of the image→h'
- Size of the object→h
➝We have to find:
- ➝Size of image(h')
➝From the above question, we get:
- u= -10cm ('-' sign as it is convex lens)
- f= 20cm
- h'=5cm
━☞Formula of lens is given by:
➝Putting the values, we get:
➝Hence, v(image distance)=-30cm
➜To find size of the image formed, we have:
╭☞Hence size of the image is 15cm