Question

8. A, B and C can do a piece of work in 10 days. A alone can do it in 40 days, and B alone can do it in 30
days. In how many days will C alone do the same work ?​

Answer 1

Answer:

• A, B and C can do piece of work in 10 days so they can do 1/10 part of work in a day
• A alone can do same work in 40 days so A can do 1/40 part of work in a day B alone can do it in 30 days so B can do 1/30 part of work in a day

Let the days taken by C be x

1/10=1/40+1/30+1/x

1/10=7/120+1/x

1/10-7/120=1/x

12-7/120=1/x

5/120=1/x

1/24=1/x

therefore C can do 1/24 in a day

so C can do whole piece of work in 24 days

Answer 2

Answer:

24

Step-by-step explanation:

A+B+C=10 effi=120/10=12

A =40 LCM=120 effi=120/40=3

B =30 effi=120/30=4

Effi of C=12-(3+4)=5

C can do the work in=120/5=24days

This is the short method n time saving also..

I hope u like this method