Math, asked by laxmiprajapati8986, 18 days ago

8. A, B and C can do a piece of work in 10 days. A alone can do it in 40 days, and B alone can do it in 30 days. In how many days will C alone do the same work?​

Answers

Answered by Soham008
1

A, B and C can do piece of work in 10 days

so they can do 1/10 part of work in a day

A alone can do same work in 40 days

so A can do 1/40 part of work in a day

B alone can do it in 30 days

so B can do 1/30 part of work in a day

let the days taken by C be x

1/10=1/40+1/30+1/x

1/10=7/120+1/x

1/10-7/120=1/x

12-7/120=1/x

5/120=1/x

1/24=1/x

therefore C can do 1/24 in a day

so C can do whole piece of work in 24 days

Answered by dayanidhisharma19
1

Answer:

The C alone will take 24 days to complete the same work

Step-by-step Explanations :

Given : A, B and C can do a piece of work in 10 days.

A alone can do it in 40 days and ,

B alone can do it in 30 days.

To find : In how many days will C alone do the same work = ?

From the given condition we can say that ,

Work done by A alone per day = 1/40

Work done by B alone per day = 1/30

So, Let the work done by C alone per day = 1/x

1/40 + 1/30 + 1/x = 1/10 ---------------- ( given )

1/x = 1/10 - [ 40 + 30 / 1200 ]

= 1/10 - [ 70/1200]

= 1/10 - 7/120

= 120 - 70 / 1200

= 50/1200 = 5/120

= 1/24

1/x = 1/24

So, x = 24 days

Hence the C alone will take 24 days to complete the same work

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