Question

8. A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red? (ii) not red?

Answer 1

Answer:

The total number of balls = No. of red balls + No. of black balls

So, the total no. of balls = 5+3 = 8

We know that the probability of an event is the ratio between the no. of favourable outcomes and the total number of outcomes.

P(E) = (Number of favourable outcomes/ Total number of outcomes)

(i) Probability of drawing red balls = P (red balls) = (no. of red balls/total no. of balls) = 3/8

(ii) Probability of drawing black balls = P (black balls) = (no. of black balls/total no. of balls) = 5/8

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Answer 2

GIVEN :

No of red balls = 3

No of black balls = 5

Total number of balls = 3balls + 5balls = 8balls

SOLUTION :

i) Probability of red

Red Balls = 3

Total Balls = 8

$hence \: probability = \frac{no \: of \: red \: balls}{total \: no \: of \: balls}$

Probability = 3/8

ii) not red

Here "not red" means the colour except red in the question i.e. black

No of black = 5

Total Balls = 8

$hence \: probabilty \: = \frac{no \: of \: black \: balls}{total \: no \: of \: balls}$

Probability =5/8