8. A bag contains 3 white and 4 black balls. One ball is
drawn and kept aside. Then one white and one black
balls are added. Now, one ball is drawn again. Find
the probability that the second ball drawn is white.
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2
Answer:
No. of white balls=3
No. of black balls= 4
probability of getting white ball in second try = 1/7
Therefore, P(E)= 1/7
Step-by-step explanation:
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Answered by
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Answer:
no. of white balls=3
no. of black balls=4
One ball of each color are added,
Thus, no. of white ball becomes =4
and, no. of black balls becomes =5
Thus total no. of balls=9
Therefore P(White ball) =1/9
Step-by-step explanation:
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