Question

8. A ball is dropped off a very tall canyon ledge. Gravity accelerates the ball at
9.8 m/s2. How fast is the ball traveling after 5 seconds?​

Answer 1

Answer:

-49 m/s

Explanation:

Apply, v = u + at

where,v is final velocity,u is initial velocity, a is the acceleration & in this case as acceleration due to gravity is acting so it will be 'g' & t is the time.

so, v= u - gt (negative sign indicates direction of acceleration due to gravity)

here , u is 0 since it is starting from rest , g is 9.8 m/ s^2 & t is 5.

Thus,putting the values we get

v= -9.8 × 5= -49 m/s (negative sign indicates direction of velocity i.e downward)