Question

8. A body of mass 2kg is placed on a rough
surface of coefficient of friction 0.8 and a
force of 10N is applied on the body. The static
frictional force acts on the body is​

Answer 1

Answer:16N

Explanation:m=2kg

Force =10N

g=10m/s^2 static frict coff: 0.8

Then max static friction =

coff stat fric × mg

2×0.8×10

1.6×10

16N

Answer 2

Concept:-

It might resemble a word or a number representation of the quantity's arithmetic value. It could resemble a word or a number that represents the numerical value of the quantity.

Given:-

Given that "A body of mass $2$ kg is placed on a rough surface of coefficient of friction $0.8$ and a force of $10$ N is applied on the body."

Find:-

We need to find that the static frictional force acts on the body is​.

Solution:-

The mass of a body $m=2$ kg

The Force applied on a body $F =10$ N

The gravity of the body $g=10m/s^2$

The static frictional force coefficient $= 0.8$

Then max static friction $=$coff stat friction $\times$ mg

$=2\times 0.8\times 10\\1.6\times 10\\=16N$

Hence, the static frictional force acts on the body is​ $16$ N.

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