Physics, asked by srinukatkuri1, 11 months ago

8.
A body starts from rest and acquires a velocity of 1000cms in 5s. Calculate
the acceleration of the body.​

Answers

Answered by MisterIncredible
7

⭐ Answer ⭐ :

✐ Given :

Initial velocity = 0m/s

Final velocity = 1000 cm/s

Time taken = 5 s

\rule{400}{4}

✑ Required to find :

  1. Acceleration of the body

\rule{400}{4}

Units Conversion ✍ :

* Before coming to the explanation part .

* However, we have to convert some units to other units .

* In the question it is given ;

Final velocity = 1000cm/s

Here we have to convert the cm/s into m/s .

This is due the fact that ,

The S.I. unit of acceleration is m/s².

Hence,

The formula used to convert the centimeters per second into meters per second .

\longrightarrow{\boxed{\Rightarrow{\boxed{1\: centimeter\:/\:second\:=\: \frac{1}{100}\: meters\:/\: second}}}}

Therefore,

\tt{\longrightarrow{\overbrace{\underbrace{1000\:cm/s = ?\:m/s}}}}

Hence;

\implies{\bold{1000\:cm\:/\:s\:=\: \frac {1000}{100}\: meters\:per\: second}}

\implies{\bold{1000\:cm\:/\:s\:=\: 10\:meters\:/\: second}}

Hence,

\fbox{\color{blue}{\longrightarrow{\boxed{Hence\:1000\:cm\:/\:s\:=\: 10\:meters\:/\: second}}}}

Similarly

Initial velocity = 0 cm/s = 0 m/s

\rule{400}{4}

☛ Explanation :

Knowing about these concepts is important to understand and solve this type of questions .

\rule{400}{1}

⚝ What is velocity ?

The displacement of the body per unit of time is know as the velocity of the body .

\longrightarrow{\textsf{The S.I. unit of velocity is <strong>meter/second</strong><strong> </strong>}}

As you know that velocity has both magnitude and direction .

So, it is a scalar quantity .

\rule{400}{1}

⚝ What is acceleration ?

The change in the velocity per unit of time is know as the acceleration .

The acceleration is represented as ;

\longrightarrow{\boxed{Acceleration\:=\: \frac {change\:in\:the\: velocity}{change\:in\:time}}}

\longrightarrow{\boxed{Acceleration\:=\: \frac {\Delta \:velocity}{\Delta \:time}}}

Here, This "" symbol is known as delta.

Here, delta ( ∆ ) represents change .

\rule{400}{1}

☑ Formula :

Let's derive the formula .

\longrightarrow{\boxed{Acceleration\:=\: \frac {\Delta \:velocity}{\Delta \:time}}}

∆ velocity refers to Final velocity (b) minus Initial velocity (u) .

similarly,

∆ Time refers to Time only

Hence ;

\longrightarrow{\boxed{Acceleration\:=\: \frac {Final\:velocity\:-\: Initial\: Velocity}{Time}}}

This implies ;

\longrightarrow{\boxed{Hence\:\:Acceleration\:=\: \frac {v\:-\:u}{time}}}

Hence, using the formula we can find the acceleration .

\rule{400}{4}

Solution ☟ :

  • Initial velocity ( u ) = 0 m/s
  • Final velocity ( v ) = 10 m/s
  • Time ( t )= 5 seconds .

Hence,

\boxed{Acceleration\:=\: \frac {\Delta \:velocity}{\Delta \:time}}

Substitute the values

we get ;

\longrightarrow{Acceleration\:=\: \frac {10m/s\:-\:0m/s}{5\: seconds}}

\longrightarrow{Acceleration\:=\: \frac {10m/s}{5\: seconds}}

\implies{Acceleration\:=\: 2 meter/{second}^{2}}

Therefore ,

\rightarrow{\boxed{\Large{Acceleration\:is\:2\:meter/{second}^{2}}}}

✅ Hence Solved . ☚

\rule{400}{6}

Answered by abdulrubfaheemi
0

Answer:

⭐ Answer ⭐ :

✐ Given :

Initial velocity = 0m/s

Final velocity = 1000 cm/s

Time taken = 5 s

\rule{400}{4}

✑ Required to find :

Acceleration of the body

\rule{400}{4}

Units Conversion ✍ :

* Before coming to the explanation part .

* However, we have to convert some units to other units .

* In the question it is given ;

Final velocity = 1000cm/s

Here we have to convert the cm/s into m/s .

This is due the fact that ,

The S.I. unit of acceleration is m/s².

Hence,

The formula used to convert the centimeters per second into meters per second .

\longrightarrow{\boxed{\Rightarrow{\boxed{1\: centimeter\:/\:second\:=\: \frac{1}{100}\: meters\:/\: second}}}}⟶

1centimeter/second=

100

1

meters/second

Therefore,

\tt{\longrightarrow{\overbrace{\underbrace{1000\:cm/s = ?\:m/s}}}}⟶

1000cm/s=?m/s

Hence;

\implies{\bold{1000\:cm\:/\:s\:=\: \frac {1000}{100}\: meters\:per\: second}}⟹1000cm/s=

100

1000

meterspersecond

\implies{\bold{1000\:cm\:/\:s\:=\: 10\:meters\:/\: second}}⟹1000cm/s=10meters/second

Hence,

\fbox{\color{blue}{\longrightarrow{\boxed{Hence\:1000\:cm\:/\:s\:=\: 10\:meters\:/\: second}}}}

\longrightarrow

Hence1000cm/s=10meters/second

Similarly

Initial velocity = 0 cm/s = 0 m/s

\rule{400}{4}

☛ Explanation :

Knowing about these concepts is important to understand and solve this type of questions .

\rule{400}{1}

⚝ What is velocity ?

The displacement of the body per unit of time is know as the velocity of the body .

\longrightarrow{\textsf{The S.I. unit of velocity is < strong > meter/second < /strong > < strong > < /strong > }}⟶The S.I. unit of velocity is < strong > meter/second < /strong > < strong > < /strong >

As you know that velocity has both magnitude and direction .

So, it is a scalar quantity .

\rule{400}{1}

⚝ What is acceleration ?

The change in the velocity per unit of time is know as the acceleration .

The acceleration is represented as ;

\longrightarrow{\boxed{Acceleration\:=\: \frac {change\:in\:the\: velocity}{change\:in\:time}}}⟶

Acceleration=

changeintime

changeinthevelocity

\longrightarrow{\boxed{Acceleration\:=\: \frac {\Delta \:velocity}{\Delta \:time}}}⟶

Acceleration=

Δtime

Δvelocity

Here, This "∆" symbol is known as delta.

Here, delta ( ∆ ) represents change .

\rule{400}{1}

☑ Formula :

Let's derive the formula .

\longrightarrow{\boxed{Acceleration\:=\: \frac {\Delta \:velocity}{\Delta \:time}}}⟶

Acceleration=

Δtime

Δvelocity

∆ velocity refers to Final velocity (b) minus Initial velocity (u) .

similarly,

∆ Time refers to Time only

Hence ;

\longrightarrow{\boxed{Acceleration\:=\: \frac {Final\:velocity\:-\: Initial\: Velocity}{Time}}}⟶

Acceleration=

Time

Finalvelocity−InitialVelocity

This implies ;

\longrightarrow{\boxed{Hence\:\:Acceleration\:=\: \frac {v\:-\:u}{time}}}⟶

HenceAcceleration=

time

v−u

Hence, using the formula we can find the acceleration .

\rule{400}{4}

Solution ☟ :

Initial velocity ( u ) = 0 m/s

Final velocity ( v ) = 10 m/s

Time ( t )= 5 seconds .

Hence,

\boxed{Acceleration\:=\: \frac {\Delta \:velocity}{\Delta \:time}}

Acceleration=

Δtime

Δvelocity

Substitute the values

we get ;

\longrightarrow{Acceleration\:=\: \frac {10m/s\:-\:0m/s}{5\: seconds}}⟶Acceleration=

5seconds

10m/s−0m/s

\longrightarrow{Acceleration\:=\: \frac {10m/s}{5\: seconds}}⟶Acceleration=

5seconds

10m/s

\implies{Acceleration\:=\: 2 meter/{second}^{2}}⟹Acceleration=2meter/second

2

Therefore ,

\rightarrow{\boxed{\Large{Acceleration\:is\:2\:meter/{second}^{2}}}}→

Accelerationis2meter/second

2

✅ Hence Solved . ☚

\rule{400}{6}

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