8.
A body starts from rest and acquires a velocity of 1000cms in 5s. Calculate
the acceleration of the body.
Answers
⭐ Answer ⭐ :
✐ Given :
Initial velocity = 0m/s
Final velocity = 1000 cm/s
Time taken = 5 s
✑ Required to find :
- Acceleration of the body
Units Conversion ✍ :
* Before coming to the explanation part .
* However, we have to convert some units to other units .
* In the question it is given ;
Final velocity = 1000cm/s
Here we have to convert the cm/s into m/s .
This is due the fact that ,
The S.I. unit of acceleration is m/s².
Hence,
The formula used to convert the centimeters per second into meters per second .
Therefore,
Hence;
Hence,
Similarly
Initial velocity = 0 cm/s = 0 m/s
☛ Explanation :
Knowing about these concepts is important to understand and solve this type of questions .
⚝ What is velocity ?
The displacement of the body per unit of time is know as the velocity of the body .
As you know that velocity has both magnitude and direction .
So, it is a scalar quantity .
⚝ What is acceleration ?
The change in the velocity per unit of time is know as the acceleration .
The acceleration is represented as ;
Here, This "∆" symbol is known as delta.
Here, delta ( ∆ ) represents change .
☑ Formula :
Let's derive the formula .
∆ velocity refers to Final velocity (b) minus Initial velocity (u) .
similarly,
∆ Time refers to Time only
Hence ;
This implies ;
Hence, using the formula we can find the acceleration .
Solution ☟ :
- Initial velocity ( u ) = 0 m/s
- Final velocity ( v ) = 10 m/s
- Time ( t )= 5 seconds .
Hence,
Substitute the values
we get ;
Therefore ,
✅ Hence Solved . ☚
Answer:
⭐ Answer ⭐ :
✐ Given :
Initial velocity = 0m/s
Final velocity = 1000 cm/s
Time taken = 5 s
\rule{400}{4}
✑ Required to find :
Acceleration of the body
\rule{400}{4}
Units Conversion ✍ :
* Before coming to the explanation part .
* However, we have to convert some units to other units .
* In the question it is given ;
Final velocity = 1000cm/s
Here we have to convert the cm/s into m/s .
This is due the fact that ,
The S.I. unit of acceleration is m/s².
Hence,
The formula used to convert the centimeters per second into meters per second .
\longrightarrow{\boxed{\Rightarrow{\boxed{1\: centimeter\:/\:second\:=\: \frac{1}{100}\: meters\:/\: second}}}}⟶
⇒
1centimeter/second=
100
1
meters/second
Therefore,
\tt{\longrightarrow{\overbrace{\underbrace{1000\:cm/s = ?\:m/s}}}}⟶
1000cm/s=?m/s
Hence;
\implies{\bold{1000\:cm\:/\:s\:=\: \frac {1000}{100}\: meters\:per\: second}}⟹1000cm/s=
100
1000
meterspersecond
\implies{\bold{1000\:cm\:/\:s\:=\: 10\:meters\:/\: second}}⟹1000cm/s=10meters/second
Hence,
\fbox{\color{blue}{\longrightarrow{\boxed{Hence\:1000\:cm\:/\:s\:=\: 10\:meters\:/\: second}}}}
\longrightarrow
Hence1000cm/s=10meters/second
Similarly
Initial velocity = 0 cm/s = 0 m/s
\rule{400}{4}
☛ Explanation :
Knowing about these concepts is important to understand and solve this type of questions .
\rule{400}{1}
⚝ What is velocity ?
The displacement of the body per unit of time is know as the velocity of the body .
\longrightarrow{\textsf{The S.I. unit of velocity is < strong > meter/second < /strong > < strong > < /strong > }}⟶The S.I. unit of velocity is < strong > meter/second < /strong > < strong > < /strong >
As you know that velocity has both magnitude and direction .
So, it is a scalar quantity .
\rule{400}{1}
⚝ What is acceleration ?
The change in the velocity per unit of time is know as the acceleration .
The acceleration is represented as ;
\longrightarrow{\boxed{Acceleration\:=\: \frac {change\:in\:the\: velocity}{change\:in\:time}}}⟶
Acceleration=
changeintime
changeinthevelocity
\longrightarrow{\boxed{Acceleration\:=\: \frac {\Delta \:velocity}{\Delta \:time}}}⟶
Acceleration=
Δtime
Δvelocity
Here, This "∆" symbol is known as delta.
Here, delta ( ∆ ) represents change .
\rule{400}{1}
☑ Formula :
Let's derive the formula .
\longrightarrow{\boxed{Acceleration\:=\: \frac {\Delta \:velocity}{\Delta \:time}}}⟶
Acceleration=
Δtime
Δvelocity
∆ velocity refers to Final velocity (b) minus Initial velocity (u) .
similarly,
∆ Time refers to Time only
Hence ;
\longrightarrow{\boxed{Acceleration\:=\: \frac {Final\:velocity\:-\: Initial\: Velocity}{Time}}}⟶
Acceleration=
Time
Finalvelocity−InitialVelocity
This implies ;
\longrightarrow{\boxed{Hence\:\:Acceleration\:=\: \frac {v\:-\:u}{time}}}⟶
HenceAcceleration=
time
v−u
Hence, using the formula we can find the acceleration .
\rule{400}{4}
Solution ☟ :
Initial velocity ( u ) = 0 m/s
Final velocity ( v ) = 10 m/s
Time ( t )= 5 seconds .
Hence,
\boxed{Acceleration\:=\: \frac {\Delta \:velocity}{\Delta \:time}}
Acceleration=
Δtime
Δvelocity
Substitute the values
we get ;
\longrightarrow{Acceleration\:=\: \frac {10m/s\:-\:0m/s}{5\: seconds}}⟶Acceleration=
5seconds
10m/s−0m/s
\longrightarrow{Acceleration\:=\: \frac {10m/s}{5\: seconds}}⟶Acceleration=
5seconds
10m/s
\implies{Acceleration\:=\: 2 meter/{second}^{2}}⟹Acceleration=2meter/second
2
Therefore ,
\rightarrow{\boxed{\Large{Acceleration\:is\:2\:meter/{second}^{2}}}}→
Accelerationis2meter/second
2
✅ Hence Solved . ☚
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