Question

8. (A body weighs 30 kg on earth. Given that the mass of earth is 6 x 1029 kg , its radius is
6.4x 106m
G = 6.7 x 10-11 Nm?kg 2. What will be
(a) the force of attraction between the body and the earth,
(b) acceleration produced in body and
(C) acceleration produced by earth ?
​

Answer 1

Answer:

F=GmM/r square

Explanation:

F=6.67×10-11×30×6×1029/6.4×106

=12,354,174-11/678.4

Answer 2

Explanation:

$\bf{\huge\mathcal{\boxed{\rm{\mathfrak\blue{Hey Mate:}}}}}$

1.

• F = GMm/r²
• = [6.67 × 10^(-11) × 6 x 10^29 × 30]/(6.4 x 10^6)²
• = 7.683 × 10^(9) N

2. We know that mg acts on a body of mass "m" on earth. So,

• mg = GmM/r²
• g = GM/r²
• = [6.67 × 10^ (-11) × 6 x 10^29 ]/(6.4 x 10^6)²
• = 9.8 m/s²

3.

• Mg = GMm/r²
• g = Gm/r²
• = 6.67 x 10^(-11) × 30/(6.4 x 10^6)²
• = 4.885 × 10^(-23) m/s²