Question

8.
A boy can open a nut by applying a force of 5 kgf at a distance of 10 cm from it
with the help of a lever. What force will he need to apply if the length of the lever
becomes 50 cm?
​

Answer 1

Answer:

1 Kgf

Explanation:

Lets the momentum be same

M1 = M2

f1r1 =f2r2

where f is force and r is replacement

let's ac to question

5kgf×10cm=50cmxf2

f2= 1Kgf

Answer 2

Concept:

• Moment of Torque
• Torque is the rotating equivalent of force in physics and mechanics.
• Depending on the subject of study, it is also known as the moment, moment of force, rotating force, or turning effect.
• It illustrates how a force can cause a change in the body's rotational motion.
• Similar to how a linear force pushes or pulls an object, a torque is a twist about a particular axis.

Given:

• Initial force F1 = 5 N
• Initial distance D1 = 10 cm = 0.1 m
• Final distance D2 = 50 cm = 0.5 m

Find:

• The final force

Solution:

Torque has to be conserved.

F1* D1 = F2* D2

5* 0.1 = F2 * 0.5

0.5 = F2* 0.5

F2 = 1

The force has to be 1 N.

#SPJ2