Question

8. A boy has x coins of 50 paisa each, 2x coins of 25 paisa each, 4x coins of 10 paisa each and 8x coins of
5 paisa each. Find the number of 5 paisa coins, if the value of all the coins is RS : 9​

Answer 1

50x+50x+40x+40x=900
180x=900
x=900/180
x=5
no. of 50 paise coins=5
no. of 25 paise coins=2×5=10
no. of 10 paise coins=4×5=20
no. of 5 paise coins=8×5=40
total no. of coins=75

Answer 2

AnswEr :

$\underline{\bigstar\:\textsf{According to the Question :}}$

$:\implies\texttt{(50 + 25 + 10 + 5) Paise Coins Value = Rs. 9}\\\\\\:\implies\tt (50 \times x) + (25 \times 2x) + (10 \times 4x) + (5 \times 8x) = (9 \times 100)\\\\\\:\implies\tt 50x + 50x + 40x + 40x = 900\\\\\\:\implies\tt 180x = 900\\\\\\:\implies\tt x = \cancel\dfrac{900}{180}\\\\\\:\implies\tt x = 5$

$\rule{150}{2}$

$\underline{\bigstar\:\textsf{Value of 5 Paise Coins :}}$

$\longrightarrow\texttt{5 Paise Coins = 8x}\\\\\\\longrightarrow\texttt{5 Paise Coins = 8(5)} \\\\\\\longrightarrow\boxed{\blue{\texttt{5 Paise Coins = 40}}}$

⠀

$\therefore\:\underline{\textsf{Hence! Value of 5 Paise Coins is \textbf{40.}}}$