Question

8. A bullet of mass 20 g comes out from the
barrel of a gun with a muzzle velocity of
400 m/s. What is the kinetic energy of the
bullet?​

Answer 1

$\huge{\dag} \: {\underline{\boxed{\sf{\purple{ ANSWER}}}}}$

Initial momentum of the system  Pi=0

Given:  Mbullet=0.02 kg      Vbullet=100 m/s         Mgun=8 kg

Let the recoil velocity of gun be V.

Applying the conservation of linear momentum :  Pf=Pi

Or   MgunV+MbulletVbullet=0

Or   8V+0.02×100=0

⟹ V=−0.25 m/s

Answer 2

Given,

A bullet of mass 20 g comes out from the  barrel of a gun with a muzzle velocity of  400 m/s.

To Find,

The kinetic energy of the bullet.

Solution,

Mass of the bullet (m) = 20 grams (0.02 kg)

Muzzle velocity (v) = 400 m/s

We know that the kinetic energy (K) = $\frac{1}{2}$ x m x $v^2$

Substituting the values,

= $\frac{1}{2}$ x 0.02 x $400^2$

= 1600 Joules

Therefore the kinetic energy of the bullet is 1600 J.

KINETIC ENERGY

Kinetic energy refers to the amount of energy produced due to motion. This energy can be used to express the amount of work that can be done by a specific object.

MUZZLE ENERGY

The muzzle energy is the kinetic energy of a gun or a bullet provided the rough value of the destructive potential of that particular gun or bullet.