Question

8.. A bus stop is barricaded from the remaining part of the road, by using 50 hollow
cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height
1 m. If the outer side of each of the cones is to be painted and the cost of painting is
12 per m², what will be the cost of painting all these cones? (Use T = 3.14 and take
V1.04 = 1.02)
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Answer 1

Answer:

surface area = A=πr(r+h2+r2)

radius = diameter/2

= 40/2 = 20 cm = .2 m

therefore,

surface area = .2π(.2+1+(.2×.2))

= .778 m^2

so surface area of 1 cone = .778 m^2

cost of painting 1 cone = .778× 12

= 9.34 rupee

cost of painting all these cones = total surface area × cost of painting per m^2

= (50×.778)× 12

= 466.8 rupee