8. A Car accelerates uniformly from 36 km/h to
In to 144 km/h 144km/h in 20s.calculate
a)The acceleration of the car
b) Distance covered by the car in the interval
Answers
Answered by
2
Answer:
acceleration = 1.5 m/s²
distance = 500m
Explanation:
given =
u = 36km/h = 10m/s
v=144km/h = 40m/s
t = 20sec
therefore , acceleration = v-u/t
= 40-10/20
= 30/20
= 3/2 =1.5 m/s²
distance travelled =
using equation
(s=ut+1/2at²)
s= 10 X 20 + 1/2 X 1.5 X 20²
= 500 m
Similar questions