Question

8. A car falls off a ledge and drops to the ground in 0.6 s. Let g=10ms-2 (for simplifying the calculations). i) What is its speed on striking the ground? ii) What is the average speed during the 0.6s ? iii) How high is the ledge from the ground ?

Answer 1

Answer:

i) Striking speed=6m/s

ii) Average speed=3m/s

iii)The ledge from the ground=1.8m

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Answer 2

Explanation:

u = 0, t = 0.6 sec, v = ? , g = 10m/sec²

(1) v = u + gt

v = 0 + 10×0.6

v = 6 m/sec

(2) average speed = (u+v)/2 = (0+6)/2

=> 3 m/sec

(3) s = ?

s = ut + 1/2gt²

s = 0×0.6 + 1/2*10*(0.6)²

s = 5*0.36 = 180 m

height of ledge = 1.8 m