Question

8. A cricket ball of mass 100g moves with a velocity 20m/s. A batsman Stops the ball in 0.05
second. Find the force applied?
​

Answer 1

Step-by-step explanation:

Given mass of the ball as 100 g after converting to mks system it becomes 0.1 kg. As we know that acceleration is nothing but rate of change velocity and in this case we have initial velocity as 20m/s and final velocity as 0.

a=(v−u)/t⇒

a=(0−20)/0.01=−2000m/s

2

F=m×a⇒

F=0.1×2000=200 N.

The hand apply equal and opposite force of 200 N.

Answer 2

Refer the above attachment

Hope it helped u ✌