Question

8. A cube of side 10 cm has a charge of 6 uC at each of its vertices. What is electric potential due to this arrangement at centre of the cube. (1) 5 MV (2) 3.2 MV (3) 2.6 MV (4) 9.2 MV ​

Answer 1

Answer:

We know the formula for electric potential is V= k.q/r where k= 9(10*9)

Now let us visualise a cube of side length a. A cube possesses 8 vertices, with each vertex having the charge 6uC. The question requires electric potential at the center of the cube.

The distance between any corner and the center of a cube is half of the body diagonal. That will be 'r' in our equation.

Therefore, V( for one charge)= 9(10*9)[6(10*-6)]/half of body diagonal

[ Body diagonal= root 3a, therefore half of body diagonal= root 3a/2]

V= 63.5(10*4) V for one charge

For 8 charges( placed on 8 vertices), V= 508(10*4) V= 5(10*6)V=5MV

Explanation:

( NOTE: The asterisk * has been used to denote powers and brackets denote multiplication.)

Hope it helps.