Question

8. A die is thrown at random. Find the probability of getting (i) 2, (ii) a number less than 3,


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Answer 1

Answer:

(I) 6/2 (ii)6/2

Step-by-step explanation:

Because there are six no in a die.

Answer 2

(I) We know that,

$p = \: \frac{number \: of \: favourable \: outcomes}{total \: number \: of \: outcomes}$

Favourable outcomes = 1 since it's only 2.

Total number of outcomes = 6

Therefore the probability becomes

$\frac{1}{6}$

(ii) We have to do the same, here in this case, the number of outcomes = 3 (Either 1, 2, 3)

Therefore the probability becomes

$\frac{3}{6}$

Which is equal to

$\frac{1}{2}$

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