Question

8) A die is thrown twice. What is the probability
of getting a prime number?
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Answer 1

Answer:

Solution

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The sum on the top can be any no. from 2 to 12.

Possible prime numbers in between 2 to 12-

2,3,5,7 and 11.

Combination for getting 2 as sum is (1,1).

∴ No. of combinations for getting 2 as a sum =1

Combinations for getting 3 as sum is (1,2),(2,1).

∴ No. of combinations for getting 5 as a sum =2

Combination for getting 5 as sum is (3,2),(2,3),(1,4),(4,1).

∴ No. of combinations for getting 5 as a sum =4

Combination for getting 7 as sum is (1,6),(6,1),(2,5),(5,2),(3,4),(4,3).

∴ No. of combinations for getting 7 as a sum =6

Combination for getting 11 as sum is (2,9)(9,2).

∴ No. of combinations for getting 11 as a sum =2

∴ Total no. of combination which gives prime no. as sum =1+2+4+6+2=15

Total no. of possible combinations =36

Probability of getting sum of the no. prime =

36

15

=

12

5

Hence the correct answer is

12

5

Step-by-step explanation:

hope it's help

Answer 2

Answer:

Here's your answer.

Step-by-step explanation:

So, prime numbers: {2, 3, 5}

We can see from the above steps that the number of favourable outcomes where we get a prime number is 3 and the total number of possible outcomes i.e. the number of elements in the sample space is 6.

So, the probability of getting a prime number is:

P(prime)=no.of prime numbers/total number of outcomes=3/6=1/2

Hence, the probability of getting a prime number is 1/2.

This is our final answer.

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